Atomic Physics

Some energy levels of a molecule are shown in the figure with their wavelengths of transitions. Then:

The radius of inner most orbit of hydrogen atom is $5.3\times\,10^{-11}m$. What is the radius of third allowed orbit of hydrogen atom?

The energy levels of an atom is shown is figure. Which one of these transitions will result in the emission of a photon of wavelength $124.1\mathrm{nm}$? Given ($h=6.62\times\,10^{-34}Js$)

$\sqrt{d_{1}}$ and $\sqrt{d_{2}}$ are the impact parameters corresponding to scattering angles $60^{\circ}$ and $90^{\circ}$ respectively, when an $\alpha\,$ particle is approaching a gold nucleus. For $d_{1}=xd_{2}$,…

Using Bohr's model, calculate the ratio of the magnetic fields generated due to the motion of the electrons in the $2^{\text{nd}}$ and $4^{\text{th}}$ orbits of hydrogen atom _______.

Radius of a certain orbit of hydrogen atom is $8.48 Ã\ldots$. If energy of electron in this orbit is $E / x$. then $x=$ _____ (Given $\mathrm{a}_0=0.529 Ã\ldots, E=$ energy of electron in ground state).

The radius of$2^{\mathrm{nd}}$orbit of$\mathrm{He}^{+}$of Bohr's model is$r_{1}$and that of fourth orbit of$\mathrm{Be}^{3+}$is represented as$r_{2}.$Now the ratio$\frac{r_{2}}{r_{1}}$is$x:1.$The value of$x$is _____?

Which of the following figure represents the variation of $\ln\,\left(\frac{R}{R_{0}}\right)$ with $\ln\,A$ (if $R=$radius of a nucleus and $A=$ its mass number)

The radius of fifth orbit of$\mathrm{Li}^{++}$is$\mathrm{_______}\times\,10^{-12}m.$Take: radius of hydrogen atom$=0.51\overset{\circ\,}{A}$

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The Bohr model is applicable to hydrogen and hydrogen-like atoms only. Reason R : The formulation of…

In Rutherford's alpha-particle scattering experiment, only a few alpha particles rebound back because A. The size of gold nucleus is very small as compared to the size of gold atom. B. Alpha particle and gold nucleus…

If an alpha particle with energy 7.7 MeV is bombarded on a thin gold foil, the closest distance from nucleus it can reach is $\_\_\_\_$ m. (Atomic number of gold $=79$ and $\frac{1}{4 \pi \epsilon_{\mathrm{o}}}=9 \times…