Atomic Physics

Some energy levels of a molecule are shown in the figure with their wavelengths of transitions. Then:

The radius of inner most orbit of hydrogen atom is $5.3\times\,10^{-11}m$. What is the radius of third allowed orbit of hydrogen atom?

Which of the following figure represents the variation of $\ln\,\left(\frac{R}{R_{0}}\right)$ with $\ln\,A$ (if $R=$radius of a nucleus and $A=$ its mass number)

In Geiger-Marsden experiment, the number of scattered $\alpha$-particles $N(\theta)$ is plotted as a function of scattering angle $\theta$. Which of the following options represents the correct plot ?

Let $T_{1}$ and $T_{2}$ be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr's model of an atom, the ratio $T_{1}$:$T_{2}$ is

Match List I with List II. \begin{array}{|l|l|l|l|}\hline & {|c|}{\begin{array}{c} List I \\(Spectral Lines of \\Hydrogen for ransitions from)\end{array}} & & {|c|}{$\begin{array}{l} \text{List II} \\ \text{(Wavelengths…

Given the value of Rydberg constant is 107 m-1, the wave number of the last line of the Balmer series in hydrogen spectrum will be:

Consider third orbit of He+ (helium), using non-relativistic approach, the speed of electron in this orbit will be given constant K=9$\times$109, Z=2 and h (Planck's Constant)= 6.6 $\times$ 10−34 J s

The ratio of wavelengths of the last line of theBalmer series and the last line of the Lyman series is_____?

Hydrogen atom in ground state is excited by a monochromatic radiation of \$\lambda=975Å.$ Number of spectral lines in the resulting spectrum emitted will be:

Consider that an electron is revolving in an excited state of Hydrogen atom with velocity $\sqrt{25.6}\times10^5$ ms$^{-1}$. The radius of the orbit is $x\times10^{-9}$ m. The value of $x$ is : [Take the mass of…

In the first excited state of hydrogen atom, the energy of its electron is $-3.4$ eV. The radial distance of the electron from the hydrogen nucleus in this case is approximately : (Take $1$ eV $= 1.6 \times 10^{-19}$ J,…