p Block Elements (Group 15, 16, 17 & 18)

Match List-I with List-II List-I(Oxo acids of Sulphur) List-II(Bonds) A Peroxodisulphuric acid $I$ Two S-OH, Four S=O,One S-O-S B Sulphuric acid $\mathrm{II}$ Two S-OH, One S=O C Pyrosulphuric acid $\mathrm{III}$ Two…

Which of the following oxoacid of sulphur has $-O-O-$ linkage?

Which of the statement given below is incorrect?

Match the Xenon compounds in Column-I with its structure in Column-II and assign the correct code: Column-I Column-II $\left(a\right)$ $XeF_{4}$ $\left(i\right)$ pyramidal $\left(b\right)$ $XeF_{6}$ $\left(ii\right)$…

Match the compounds of Xe in column I with the molecular structure in column II. Column-I Column-II (a) $\mathrm{XeF}_{2}$ (p) Square planar (b) $\mathrm{XeF}_{4}$ (q) Linear (c) $\mathrm{XeO}_{3}$ (r) Square pyramidal…

Match List I (substances) with List II (processes employed in the manufacture of the substances) and select the correct option.

Match list-I with List-II : List - I List - II A. Coke I. Carbon atoms are$\mathrm{sp}^{3}$hybridised B. Diamond II. Used as dry lubricants C. Fullerene III. Used as a reducing agent D. Graphite IV. Cage like molecules…

$\left(a\right)H_{2}O_{2}+O_{3}\rightarrow\,H_{2}O+2O_{2}$ $\left(b\right)H_{2}O_{2}+Ag_{2}O\rightarrow\,2Ag+H_{2}O+O_{2}$ Role of hydrogen peroxide in the above reactions is respectively:

Given below are two statements : one is labelled as Assertion$\left(A\right)$ and the other is labelled as Reason $\left(R\right)$. Assertion $\left(A\right)$: $\mathrm{ICl}$ is more reactive than $I_{2}$. Reason…

Match List - I with List - II: List-I (Species) List-II (Number of lone pairs of electrons on the central atom) (a) $\mathrm{XeF}_{2}$ (i) $0$ (b) $\mathrm{XeO}_{2}F_{2}$ (ii) $1$ (c) $\mathrm{XeO}_{3}F_{2}$ (iii) $2$…

Which among the following is the most reactive?

Match List-I with List-II : List-I List-II Industrial process Application (a) Haber's process (i) $\mathrm{HNO}_{3}$ synthesis (b) Ostwald's process (ii) Aluminium extraction (c) Contact process (iii) $\mathrm{NH}_{3}$…