p Block Elements (Group 13 & 14)

Which of the following is the most basic oxide?

Match the following and identify the correct option. (a) $\mathrm{CO}\left(g\right)+H_{2}\left(g\right)$ (i) $\mathrm{Mg}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}$ (b) Temporary…

A group 13 element $^{'}X^{'}$ reacts with chlorine gas to produce a compound $\mathrm{XCl}_{3}.\mathrm{XCl}_{3}$ is electron deficient and easily reacts with…

The ratio of number of water molecules in Mohr's salt and potash alum is $\times\,10^{-1}.$ (Integer answer)

The number of$2$-centre-$2$-electron and$3$-centre-$2$-electron bonds in$B_{2}H_{6}$, respectively, are:

It is noticed that $\mathrm{Pb}^{2+}$ is more stable than $\mathrm{Pb}^{4+}$ but $\mathrm{Sn}^{2+}$ is less stable than $\mathrm{Sn}^{4+}$. Observe the following reactions. $\mathrm{PbO}_{2}+\mathrm{Pb} \rightarrow 2…

Given below are two statements : Statement (I) : The first ionisation enthalpy of group 14 elements is higher than the corresponding elements of group 13. Statement (II) : Melting points and boiling points of group 13…

Evaluate the following statements related to group 14 elements for their correctness. (A) Covalent radius decreases down the group from \(\mathrm{C}\) to \(\mathrm{Pb}\) in a regular manner. (B) Electronegativity…

The number of neutrons present in the more abundant isotope of boron is ' \(x\) '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' \(y\) '. The value of \(x+y\) is…

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): In expensive scientific instruments, silica gel is kept in watch-glasses or in semipermeable…

Match List-I with Match List-II List-I (Metal) List-II (Application) (A) $Cs$ (I) High temperature thermometer (B) $Ga$ (II) Water repellent sprays (C) $B$ (III) Photoelectric cells (D) $Si$ (V) Bullet proof vest Choose…

When borax is heated with $CoO$on a platinum loop, blue coloured bead formed is largely due to