Chemical Kinetics

For a reaction $A\rightarrow\,B,$enthalpy of reaction is $-4.2\mathrm{kJ}\mathrm{mol}^{-1}$ and enthalpy of activation is $9.6\mathrm{kJ}\mathrm{mol}^{-1}.$The correct potential energy profile for the reaction is shown…

The given graph is a representation of kinetics of a reaction. The $y$ and $x$ axes for zero and first order reactions, respectively are

Mechanism of a hypothetical reaction $X_{2}+Y_{2}\rightarrow\,2\mathrm{XY}$ is given below: (i) $X_{2}\rightarrow\,X+X\left(\mathrm{fast}\right)$ (ii) $X+Y_{2}\rightleftharpoons\,\mathrm{XY}+Y\left(\mathrm{slow}\right)$…

What is the correct difference between first and second order reactions?

The rate of a first-order reaction is $0.04moll^{-1}s^{-1}$ at $10$ second and $0.03moll^{-1}s^{-1}$ at $20$ seconds after initiation of the reaction. The half-life period of the reaction is:

When initial concentration of a reactant is doubled in a reaction, its half-life period is not affected. The order of the reaction is:

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to $\frac{h^{2}}{x\mathrm{ma}_{0}^{2}}.$The value of $10x$ is ($a_{0}$ is radius of Bohr's orbit) (Nearest integer) [Given:…

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to $\frac{h^{2}}{x\mathrm{ma}_{0}^{2}}.$The value of $10x$ is ($a_{0}$ is radius of Bohr's orbit) (Nearest integer) [Given:…

In the nuclear transmutation $_{4}^{9}\text{Be}+\text{X}⟶_{4}^{8}\text{Be}+\text{Y}$, identify $(X,Y)$.

Statement $1 \mathrm{~Pb}^{4+}$ compounds are stronger oxidising agents than $\mathrm{Sn}^{4+}$ compounds. Statement 2 The higher oxidation states for the group 14 elements are more stable for the heavier members of the…

$\mathrm{XmL}$ of $\mathrm{H}_{2}$ gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical conditions is :

Assertion : The position of an element in periodic table after emission of one $\alpha$ - and two $\beta$-particles remains unchanged. Reason : Emission of one $\alpha$ - and two $\beta$-particles give isotope of the…