Carboxylic Acid Derivatives

The product formed from the following reaction sequence is:

Which of the following acid will form an (a) Anhydride on heating and (b) Acid imide on strong heating with ammonia?

Consider the above reaction and predict the major product.

In the following sequence of reactions a compound $A,$ (molecular formula $C_{6}H_{12}O_{2}$) with a straight chain structure gives a $C_{4}$ carboxylic acid. $A$ is :…

The major product of the following reaction is: $CH_{3}CH=CHCO_{2}CH_{3}\overset{LiAlH_{4}}{\rightarrow\,}$

An organic compound A upon reacting with $\mathrm{NH}_{3}$gives B. On heating, B gives C. C in presence of KOH reacts with Br2 to give CH3CH2NH2. A is :

Identify the product \((\mathrm{P})\) in the following reaction:

In Friedel-Crafts alkylation of aniline, one gets:

Two isomers$(A)$ and$(B)$ with Molar mass$184g/mol$and elemental compositio $C,52.2\%;H,49\%$and$Br42.9\%$gave benzoic acid and$p-$bromobenzoic acid, respectively on oxidation with$KMnO_{4}$. Isomer$'A'$is optically…

Find out the major product for the above reaction.

Decarboxylation of all six possible forms of diaminobenzoic acids$C_{6}H_{3}(NH_{2})_{2}COOH$yields three products$A,B$and$C$. Three acids give a product '$A$', two acids gives a product '$B$' and one acid give a…

The reagent, from the following, which converts benzoic acid to benzaldehyde in one step is