Indefinite Integration

$\int \sqrt{x+\sqrt{x^2+2}} d x=$

$\int \frac{x^3-1}{x^3+x} d x=$

$\int \frac{x^3-1}{x^3+x} d x=$

The value of $\int e^{\tan \theta}(\sec \theta-\sin \theta) d \theta$ is

$\int \sqrt{x+\sqrt{x^2+2}} d x=$

Value of $\int \frac{d x}{\sqrt{x(a-x)}}$ is

$\int \tan ^{-1} \sqrt{\mathrm{x}} \mathrm{dx}$ is equal to

$\int \frac{x+3}{(x+4)^2} e^x d x$ is equal to

If $\int \frac{\mathrm{e}^{\mathrm{x}}(1+\sin \mathrm{x}) \mathrm{dx}}{1+\cos \mathrm{x}}=\mathrm{e}^{\mathrm{x}} \mathrm{f}(\mathrm{x})+\mathrm{C}$, then $\mathrm{f}(\mathrm{x})$ is equal to

Let $f(x)=\int \frac{x^2 d x}{\left(1+x^2\right)\left(1+\sqrt{\left.1+x^2\right)}\right.}$ and $f(0)=0$, then the value of $f(1)$ be

The value of $\int \frac{1}{\left[(x-1)^3(x+2)^5\right]^{\frac{1}{4}}} d x$, is

If $\int \frac{3 x+1}{(x-3)(x-5)} d x=\int \frac{-5}{(x-3)} d x+\int \frac{B}{(x-5)} d x$ then the value of $B$ is