Wave Optics

Assertion : Diffraction is common in sound but not common in light waves. Reason : Wavelength of light is more than the wavelength of sound.

In a Young's double slit experiment, a light of wavelength $500 \mathrm{~nm}$ falls on it. Its slits separation is $2 \mathrm{~mm}$ and distance between plane of slits and screen is $2 \mathrm{~m}$ then, find distance…

Light of wavelength $6000 Å$ falls on a single slit of width $0.1 \mathrm{~mm}$. The second minima will be formed for the angle of diffraction of

The distance between the first dark and bright fringes formed in Young's double slit experiment with band width $B$ is

Assertion : Colours are seen in thin layers of oil on the surface of water. Reason : White light is composed of several colours.

The head lights of a jeep are $1.2 \mathrm{~m}$ apart. If the pupil of the eye of an observer has a diameter of $2 \mathrm{~mm}$ and light of wavelength $5896 Å$ is used, what should be the maximum distance of the jeep…

Assertion : In Young's double slit experiment, interference pattern disappears when one of the slits is closed. Reason : Interference occurs due to superposition of light waves from two coherent sources.

Light is incident on a polarizer with intensity $I_0$. A second prism called analyzer is kept at a angle of $15^{\circ}$, from the first polarizer then the intensity of final emergent light will be

In a single slit diffraction the distance between plane of slit and screen is $1 \mathrm{~m}$. The size of the slit is $0.7 \mathrm{~mm}$ and second maximum is formed at the distance of $2 \mathrm{~mm}$ from the centre…

Assertion : Two point coherent sources of light $S_1$ and $S_2$ are placed on a line as shown. $P$ and $Q$ are two points on that line. If at point $\mathrm{P}$ maximum intensity is observed then maximum intensity…

Two slits are separated by a distance of 0.5 mmand illuminated withlight of wavelength $\lambda=6000 Å$. If the screen is placed at $2.5 \mathrm{~m}$ from the slits. The distance of the third bright fringe from the…

Assertion : In YDSE bright and dark fringe are equally spaced. Reason : It only depends upon phase difference.